Australian Open 2019: Lucas Pouille edges Milos Raonic to reach maiden grand slam semis

Updated on Jan 23, 2019 01:38 PM IST

Lucas Pouille became the first Frenchman to reach the semi-finals of the Australian Open since Jo-Wilfried Tsonga in 2010 when he stunned Canada’s 16th seed Milos Raonic on Wednesday.

France's Lucas Pouille celebrates after winning the match against Canada's Milos Raonic.(REUTERS)
France's Lucas Pouille celebrates after winning the match against Canada's Milos Raonic.(REUTERS)
Melbourne | ByReuters

Frenchman Lucas Pouille tamed big-serving Milos Raonic 7-6(4), 6-3, 6-7(2), 6-4 in the Australian Open quarter-final to advance to his maiden Grand Slam semi-final on Wednesday.

The Frenchman, 24, took the first set with a brilliant forehand pass against an advancing Raonic in the tiebreak and converted his only breakpoint opportunity in the second set with a measured backhand lob before two winners and two big serves gave Pouille the second stanza.

READ: Sarfraz Ahmed faces backlash after alleged racist comment on Phehlukwayo

The 28-year-old Raonic made former top 10 player Pouille pay for wasting four breakpoints by winning the third set tiebreaker but the Frenchman broke the Canadian again in the fourth, converting his third matchpoint to seal the contest in just over three hours.

Pouille will meet the winner of the last quarter-final between top-seeded Serb Novak Djokovic and Kei Nishikori of Japan for a place in Sunday’s final.

SHARE THIS ARTICLE ON
SHARE
Story Saved
×
Saved Articles
Following
My Reads
My Offers
Sign out
New Delhi 0C
Thursday, September 29, 2022
Start 15 Days Free Trial Subscribe Now
Register Free and get Exciting Deals