So-called Einstein puzzles, which you have solved with me before, can come in both full-length and miniature varieties, with fewer variables. It’s a full-length Einstein puzzle this week, which means it requires a lengthy description. Besides, there are also your answers to discuss from last week. In view of the tightness of space, therefore, let us go straight to the point.
Welcome to Problematics! (Shutterstock)
#Puzzle 42.1
#Puzzle 42.1
Five people, each from a different profession, sit on a bench while their dogs play in the park. The dogs are 85, 86, 87, 88 and 89 months old, while the humans are 85, 86, 87, 88 and 89 years old, but not necessarily in the same order.
* Alpha is a pug, Beta is a mastiff, and Delta is a beagle.
* The 86-year-old’s pet is Gamma, the 88-year-old’s pet is a spaniel, and the 89-year-old’s pet is Alpha, who is 85 months old.
* The singer’s pet is Epsilon, while the painter’s pet is a Labrador retriever.
* The actor is 89 years old.
* The singer sits in the middle, two persons on either side.
* At one end sits a person whose pet is 87 months old.
* Two persons sitting next to each other have pets who are 87 and 88 months old.
* The teacher sits next to the person whose pet is the beagle; the author sits next to the person whose pet is 88 months old.
* The painter sits to the left of the person whose pet is 85 months old.
* Delta’s owner sits to the right of the 87-year-old, who sits to the right of the person whose pet is 86 months old.
Who has which pet, who is how old, etc? As usual, your answer will work best in a table format.
Puzzle #42.2
Find a word of four letters, consisting entirely of vowels (no Y, no consonant). It’s listed in Collins English Dictionary.
Mailbox: Last week’s solvers
#Puzzle 41.1
This is a variation of the popular Monty Hall Problem. The better choice is to switch after the trickster reveals one Jack.
Suppose the 3 cards are A, B, C from left to right, and suppose we choose A. There are 3 possibilities:
* A is the Queen; the trickster reveals either of B or C
* B is the Queen; the trickster reveals C
* C is the Queen, the trickster reveals B
By switching, we win in the latter 2 cases, but not in the first. So, the probability becomes 2/3, while with our original choice it was 1/3.
— Arsh Gupta, Gurgaon
Indeed, Arsh. If you chose a Jack first (probability 2/3), then your choice will dictate which card the trickster must turn face up. Only if you chose the Queen first (probability 1/3) does the trickster have freedom of choice.
The highest scoring word is obviously ZZZ (signifying that one is asleep). Among acceptable answers received (dictionary words only), the next highest scorers are ZUZ (an ancient Hebrew coin) and SWY (a gambling game).
#Puzzle 41.2
Problematics will be back next week. Please send in your replies by Friday noon to problematics@hindustantimes.com
Puzzles Editor Kabir Firaque is the author of the weekly column Problematics. A journalist for three decades, he also writes about science and mathematics.
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Home/Editors Pick/Problematics | The Who’s Who Of Dogs And Humans In The Park
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